Câble InLine TAE-F allemand / RJ45 8P2C 10 m

The InLine TAE-F German RJ45 8P2C Cable (10 m) has a TAE-F connector on one end and an RJ45 8P2C plug on the other, suitable for direct wiring between a German TAE wall socket and a router. This 2-wire cable is compatible with devices such as FritzBox 7170 and 7270 for a direct connection without a splitter.

Advantages

The cable provides a straightforward physical connection between a TAE-F socket and an RJ45 network port, simplifying setup by eliminating the need for a separate splitter. At 10 metres length it offers flexibility in device placement. The black, durable cable construction is intended for repeated use and stable signal transmission for voice/data applications supported by compatible routers.

Suitable for

• Direct connection of FritzBox 7170 and 7270 to a TAE-F wall socket
• Connecting a router to a German TAE telephone outlet without a splitter
• Home or small office installations requiring a 10 m TAE-F to RJ45 lead

Key specifications

• Brand: InLine
• Model/MPN: 18510
• EAN: 4043718187607
• Cable length: 10 m
• Connector 1: TAE-F
• Connector 2: RJ45 (8P2C)
• Wiring: 2-wire
• Colour: Black

How to use

Insert the TAE-F connector into the German TAE wall socket and plug the RJ45 8P2C connector into the router's corresponding DSL or telephone RJ45 port as specified by the router manual. Ensure both ends are firmly seated. Power on the router and follow the router's setup instructions for line configuration. This cable is intended for direct physical connection and does not provide line splitting or additional signal conversion.

Recommendations

Use this cable where a direct connection between a TAE-F outlet and a router is required and where the router supports a 2-wire TAE-to-RJ45 connection (for example FritzBox 7170/7270). Avoid running the cable near strong electromagnetic sources and do not bend sharply to preserve signal integrity.